To get this configuration it is enough to get a configuration for some X \geq T/4, because we can then apply Type 2 moves until the number of coins in the fourth box is reduced to T/4.įinally, one can obtain such a configuration using compound move 4. We will be done if we can obtain the configuration, for then we can apply two compound move 1s to get the. do type 2 with first box (exchanging 1s) to then as before. to to to to (type 2 moves exchanging zeros) last box is zero last box is 3 (do type 2 with first box) The Polymath Project aims to encourage a holistic approach to learning, which does not isolate academic disciplines, but recognizes the many ways in which they overlap. TO MAKE THE FINAL BOX AS SMALL AS POSSIBLE WITH ALL OTHERS ZERO The structure Take 7, multiply by two, do 2 to power, do 2 double up-arrow, do 2 double up-arrow, do 2 to power, multiply by 2. We will summarize progress on the Polymath wiki page. Discussion of the project of a non-research nature should continue in the Polymath proposal page.
POLYMATH PROJECT HOW TO
Sorry can't see how to do a double Knuth uparrow This project is a follow-up to Aubrey de Grey’s breakthrough result that the chromatic number of the plane is at least 5. Remove one coin from B_j and add two coins to B_,0,0,0] Type 1: Choose a nonempty box B_j with 1 \leq j \leq 5. There are two types of operation allowed: Problem In each of six boxes B_1, B_2, B_3, B_4, B_5, B_6 there is initially one coin. The question to be solved is Question 5 of the 2010 International Mathematical Olympiad:
POLYMATH PROJECT UPDATE
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